Question

solve for \x\.
\\(\frac{x}{4} + \frac{2}{3} = \frac{1}{6}\\)
\\(x = \square\\)

Explanation:

Step1: Subtract $\frac{2}{3}$ from both sides

$\frac{x}{4} = \frac{1}{6} - \frac{2}{3}$

Step2: Find a common denominator for the right side (6)

$\frac{x}{4} = \frac{1}{6} - \frac{4}{6}$

Step3: Subtract the fractions on the right

$\frac{x}{4} = -\frac{3}{6}$

Step4: Simplify $-\frac{3}{6}$ to $-\frac{1}{2}$

$\frac{x}{4} = -\frac{1}{2}$

Step5: Multiply both sides by 4 to solve for x

$x = -\frac{1}{2} \times 4$

Step6: Calculate the product

$x = -2$

Answer:

-2