Question

solve for n.
$\frac{3}{2}-\frac{1}{2}n = 2n + 3$
$n=square$

Explanation:

Step1: Move terms with n to one side

Add $\frac{1}{2}n$ to both sides: $\frac{3}{2}=2n+\frac{1}{2}n + 3$.

Step2: Combine like - terms

$2n+\frac{1}{2}n=\frac{4n + n}{2}=\frac{5n}{2}$, so $\frac{3}{2}=\frac{5n}{2}+3$.

Step3: Move the constant to the left - hand side

Subtract 3 from both sides: $\frac{3}{2}-3=\frac{5n}{2}$. Since $3=\frac{6}{2}$, then $\frac{3}{2}-\frac{6}{2}=-\frac{3}{2}$, so $-\frac{3}{2}=\frac{5n}{2}$.

Step4: Solve for n

Multiply both sides by $\frac{2}{5}$: $n =-\frac{3}{2}\times\frac{2}{5}=-\frac{3}{5}$.

Answer:

$-\frac{3}{5}$