solve for d. $2^{d} = 32$ $d = \\square$

$solve for d. $2^{d} = 32$ $d = \\square$$

solve for d.
$2^{d} = 32$
$d = \square$

We know that $32 = 2^5$, so the equation $2^d = 32$ can be rewritten as $2^d = 2^5$.

If $a^m = a^n$ (where $a>0$ and $a
eq1$), then $m = n$. Here, $a = 2$, $m = d$, and $n = 5$. So we can conclude that $d = 5$.

$5$