Question

identify a, b and c.
$x^2 - 8x + 18 = 0$
$a = \square$
$b = \square$
$c = \square$

Explanation:

Step1: Recall quadratic form

The standard quadratic equation is \(ax^2 + bx + c = 0\), where \(a\) is the coefficient of \(x^2\), \(b\) is the coefficient of \(x\), and \(c\) is the constant term.

Step2: Identify \(a\)

For the equation \(x^2 - 8x + 18 = 0\), the coefficient of \(x^2\) is \(1\) (since \(x^2 = 1x^2\)), so \(a = 1\).

Step3: Identify \(b\)

The coefficient of \(x\) is \(-8\) (from \(-8x\)), so \(b = -8\).

Step4: Identify \(c\)

The constant term (the term without \(x\)) is \(18\), so \(c = 18\).

Answer:

\(a = 1\), \(b = -8\), \(c = 18\)