Question

$-\frac{1}{2}(16x - 4)leq2x - 18$

Explanation:

Step1: Distribute the -1/2

$-\frac{1}{2}(16x - 4)=-8x + 2$
So the inequality becomes $-8x + 2\leq2x-18$.

Step2: Move x - terms to one side

Add 8x to both sides:
$2\leq2x + 8x-18$
$2\leq10x-18$.

Step3: Move constant terms to the other side

Add 18 to both sides:
$2 + 18\leq10x$
$20\leq10x$.

Step4: Solve for x

Divide both sides by 10:
$\frac{20}{10}\leq x$
$x\geq\frac{10}{3}$.

Answer:

$x\geq\frac{10}{3}$