QUESTION IMAGE
Question
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Step1: Analyze the system of equations
The given system is \(
\). Let's rewrite both equations in slope - intercept form (\(y=mx + b\), where \(m\) is the slope and \(b\) is the y - intercept).
For the first equation \(x - y=7\), we can solve for \(y\):
\(y=x - 7\), so the slope \(m_1 = 1\) and the y - intercept \(b_1=-7\).
For the second equation \(x - y=-4\), we solve for \(y\):
\(y=x + 4\), so the slope \(m_2 = 1\) and the y - intercept \(b_2 = 4\).
Step2: Determine the nature of the lines
Since the slopes of the two lines (\(m_1=m_2 = 1\)) are equal and the y - intercepts (\(b_1=-7\) and \(b_2 = 4\)) are different, the two lines are parallel. Parallel lines never intersect, so the system of equations has no solution.
Step3: Graphical interpretation (optional but for verification)
If we were to graph \(y=x - 7\) and \(y=x + 4\), we would start by plotting the y - intercepts. For \(y=x - 7\), we plot the point \((0,-7)\) and then use the slope (rise 1, run 1) to draw the line. For \(y=x + 4\), we plot the point \((0,4)\) and then use the slope (rise 1, run 1) to draw the line. We would observe that the two lines are parallel and do not intersect.
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The system of equations \(
\) has no solution because the two lines represented by the equations are parallel (they have the same slope \(m = 1\) and different y - intercepts) and parallel lines do not intersect.