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13) $4(5r^2 - r - 2)$ a) $12r^2 - 12r - 16$ b) $16r^4 + 32r^3 - 32r^2$ …

Question

  1. $4(5r^2 - r - 2)$

a) $12r^2 - 12r - 16$
b) $16r^4 + 32r^3 - 32r^2$
c) $20r^2 - 4r - 8$
d) $15r^2 - 15r + 15$

Explanation:

Step1: Distribute 4 to each term

\(4 \times 5r^2 = 20r^2\)

Step2: Multiply 4 by -r

\(4 \times (-r) = -4r\)

Step3: Multiply 4 by -2

\(4 \times (-2) = -8\)

Step4: Combine the results

\(20r^2 - 4r - 8\)

Answer:

C) \(20r^2 - 4r - 8\)