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match each population growth model to the graph that best represents it…

Question

match each population growth model to the graph that best represents it. linear growth logistic growth exponential growth

Explanation:

Step1: Analyze Linear Growth

Linear growth has a constant slope (constant rate of change). Let's check the first graph: at t=3, p≈5; t=6, p≈10? Wait, no, first graph: t=0, p=0; t=3, p≈5; t=6, p≈10? Wait, no, looking at the first graph (left): the points seem to have a constant difference? Wait, maybe the middle graph? Wait, no, let's recall:

  • Linear growth: constant increase per unit time (straight line, constant slope).
  • Exponential growth: increasing by a constant ratio (curving upwards, increasing rate).
  • Logistic growth: S - shaped, starts with exponential - like, then levels off.

First graph (left): Let's check the differences. At t=0, p=0; t=3, p≈5; t=6, p≈10; t=9, p≈15; t=12, p≈20; t=15, p≈30; t=18, p≈40? Wait, no, the left graph's y - axis: 0,15,30,45,60,75. At t=0, p=0; t=3, p≈5? No, maybe the left graph is linear? Wait, no, the middle graph: t=0, p=0; t=3, p≈30; t=6, p≈80; t=9, p≈190; t=12, p≈260; t=15, p≈290; t=18, p≈290. Wait, no, the right graph: t=0, p=2; t=3, p=4; t=6, p=8; t=9, p=11? No, t=0, p=2; t=3, p=4 (double); t=6, p=8 (double again); t=9, p=11? No, wait t=9: p=11? No, the right graph's y - axis: 0,4,8,12,16,20. t=0, p=2; t=3, p=4 (ratio 2); t=6, p=8 (ratio 2); t=9, p=11? No, maybe t=9, p=11? No, maybe I misread. Wait, the right graph: t=0, p=2; t=3, p=4; t=6, p=8; t=9, p=11? No, that's not exponential. Wait, maybe the middle graph is exponential? Wait, no, let's correct:

  • Linear growth: constant difference. So if the left graph has points with constant difference (e.g., each time t increases by 3, p increases by a constant amount). Let's check left graph:

t: 0, 3, 6, 9, 12, 15, 18

p: 0, ~5, ~10, ~15, ~20, ~30, ~40? Wait, no, the left graph's y - axis is 0,15,30,45,60,75. So at t=0, p=0; t=3, p≈5? No, maybe the left graph is linear (constant slope), middle is logistic (levels off at the end), right is exponential.

Wait, let's re - identify:

  1. Linear growth: The graph with constant slope (straight line, constant increase). So the left graph: let's check the slope. From t=0 to t=18, p goes from 0 to 70? No, maybe the left graph is linear (each time t increases by 3, p increases by a constant amount).
  1. Exponential growth: The graph with increasing slope (curving upwards, like the right graph? Wait, the right graph: t=0, p=2; t=3, p=4; t=6, p=8; t=9, p=11? No, t=9, p=11 is not double of 8. Wait, maybe the middle graph is exponential? No, the middle graph at t=15 and t=18 is flat, so that's logistic (levels off).
  1. Logistic growth: S - shaped, starts with exponential, then levels off. So middle graph: starts increasing rapidly, then levels off (t=15 and t=18 same), so logistic.
  1. Exponential growth: right graph? Wait, t=0, p=2; t=3, p=4 (ratio 2); t=6, p=8 (ratio 2); t=9, p=11? No, t=9, p=11 is not 8*1.5. Wait, maybe the right graph is exponential (since it's doubling: t=0:2, t=3:4, t=6:8, t=9:11? No, maybe my mistake. Wait, the left graph: t=0, p=0; t=3, p=5; t=6, p=10; t=9, p=15; t=12, p=20; t=15, p=30; t=18, p=40? No, the y - axis for left is 0,15,30,45,60,75. So t=0:0, t=3:5 (no), maybe the left graph is linear (constant slope), middle is logistic (levels off), right is exponential.

Wait, let's recall the definitions:

  • Linear growth: \( P(t)=mt + b \), constant slope \( m \).
  • Exponential growth: \( P(t)=P_0e^{rt} \) or \( P(t)=P_0a^t \), increasing by a constant ratio.
  • Logistic growth: \( P(t)=\frac{K}{1 + e^{-r(t - t_0)}} \), S - shaped, approaches carrying capacity \( K \).

So:

  • Left graph: The points seem to have a constant rate of increase (linear), so linear growth.
  • Middle g…

Answer:

  • Linear growth: The Left Graph (first graph)
  • Logistic growth: The Middle Graph (second graph)
  • Exponential growth: The Right Graph (third graph)