Question

masteryconnect
scott, trinity
cgw 25-26 alg 1 semester exam
12 of 50
given $r = 2v + 2z$, solve the equation for $z$.
\\( z = r - 2v \\)
\\( z = \frac{r - 2v}{2} \\)
\\( z = \frac{r + 2v}{2} \\)
\\( z = \frac{2v - r}{2} \\)

Explanation:

Step1: Isolate terms with z

Start with the equation \( r = 2v + 2z \). Subtract \( 2v \) from both sides to get \( r - 2v = 2z \).

Step2: Solve for z

Divide both sides of \( r - 2v = 2z \) by 2. This gives \( z=\frac{r - 2v}{2} \).

Answer:

\( z=\frac{r - 2v}{2} \) (the second option, e.g., if the options are labeled as A, B, C, D with B being \( z=\frac{r - 2v}{2} \), then B. \( z=\frac{r - 2v}{2} \))