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Question
a man possesses an allele for a recessive x - linked genetic condition, and his wife does not possess the allele. what are the odds that the couples son will express the condition? 0% 25% 50% 100%
Step1: Understand X - linked inheritance
In X - linked inheritance, males have one X and one Y chromosome (XY), and females have two X chromosomes (XX). A male passes his Y chromosome to his sons and his X chromosome to his daughters.
Step2: Analyze the parents' chromosomes
The man has the allele for the recessive X - linked condition on his X chromosome. His wife does not have the allele. Sons inherit their X chromosome from their mother and Y chromosome from their father.
Step3: Determine the son's genotype
Since the son gets his X chromosome from his mother (who does not have the allele for the recessive X - linked condition) and his Y chromosome from his father, the son will not have the recessive allele on his X chromosome. So the probability of the son expressing the recessive X - linked condition is 0.
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