Question

to make an international telephone call, you need the code for the country you are calling. the codes for country a, country b, and c are three consecutive integers whose sum is 102. find the code for each country. countrys a code is . countrys b code is , and countrys c code is .

Explanation:

Step1: Let the first integer (country's A code) be $x$.

Since the codes are consecutive integers, country's B code is $x + 1$ and country's C code is $x+2$.

Step2: Set up the sum equation.

The sum of the three consecutive integers is $x+(x + 1)+(x+2)$. We know the sum is not given in full in the problem - but if we assume the sum is $S$, then $x+(x + 1)+(x+2)=S$. Simplifying the left - hand side gives $3x+3 = S$.

Step3: Solve for $x$.

First, subtract 3 from both sides: $3x=S - 3$. Then divide both sides by 3: $x=\frac{S - 3}{3}$.
Let's assume the sum of the three consecutive integers is 102 (since the text mentions "102. Find the code for each country" without proper context, we'll work with this number).
If $S = 102$, then $x=\frac{102-3}{3}=\frac{99}{3}=33$.

Step4: Find the other codes.

Country's B code: $x + 1=33 + 1 = 34$.
Country's C code: $x+2=33 + 2 = 35$.

Answer:

Country's A code is 33, country's B code is 34, country's C code is 35.