Question

let’s do a few together, step by step. example one: solve the quadratic equation. $8x^2 + 14x = -5$ first rewrite the equation in standard form (select the correct equation.) $-8x^2 + 14x + 5 = 0$ $8x^2 + 14x + 5 = 0$ $8x^2 - 14x + 5 = 0$ $8x^2 - 14x - 5 = 0$

Explanation:

Step1: Recall standard quadratic form

The standard form of a quadratic equation is \( ax^2 + bx + c = 0 \), where \( a
eq 0 \).

Step2: Rewrite the given equation

We start with the equation \( 8x^2 + 14x = -5 \). To convert it to standard form, we add \( 5 \) to both sides of the equation.

Adding \( 5 \) to both sides:
\( 8x^2 + 14x + 5 = -5 + 5 \)

Simplifying the right - hand side (since \( - 5+5 = 0 \)) gives us \( 8x^2 + 14x + 5 = 0 \).

Answer:

\( 8x^2 + 14x + 5 = 0 \) (the second option in the given set of equations)