Question

4 leslie has a miniature car powered by an air tank. the car weighs 3.44 kg, and the air tank produces a force of 40.2 n. leslie releases the car from rest, and it begins accelerating. after a period of 2.95 seconds, what distance has the miniature car traveled?
50.8 m
11.7 m
17.2 m
35.5 m

Explanation:

Step1: Calculate the acceleration

According to Newton's second law \(F = ma\), where \(F = 40.2\space N\) and \(m=3.44\space kg\). Then \(a=\frac{F}{m}\).

$$a=\frac{40.2}{3.44}\approx11.7\space m/s^{2}$$

Step2: Use the kinematic equation \(x = v_{0}t+\frac{1}{2}at^{2}\)

Since the car starts from rest, \(v_{0} = 0\space m/s\), \(t = 2.95\space s\), and \(a\approx11.7\space m/s^{2}\).

$$x=\frac{1}{2}\times11.7\times(2.95)^{2}$$

$$x = 0.5\times11.7\times8.7025$$

$$x=50.8\space m$$

Answer:

50.8 m