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a kayaker moves 26 meters southward, then 18 meters northward, and fina…

Question

a kayaker moves 26 meters southward, then 18 meters northward, and finally 12 meters southward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn = (tap field to change.)

Explanation:

Step1: Calculate the distance

Distance is the total length of the path covered.
$$26 + 18+12$$
$$=56$$

Step2: Calculate the displacement

Let southward be positive and northward be negative.
Displacement \(d=(26)+(- 18)+(12)\)
$$d = 26 - 18+12$$
$$d=20$$
Since \(d>0\), the direction is southward.

Answer:

Distance \(= 56\) m
Magnitude of displacement \(=20\) m
Dir'n = Southward