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juanita is testing her new model airplane. she starts its descent at an…

Question

juanita is testing her new model airplane. she starts its descent at an elevation of 2,500 feet. it descends at a constant rate of 500 feet per minute. what is the vertical intercept for this line? in other words, at what elevation did the plane start to descend? the slope is -500. the vertical intercept is \boxed{}.

Explanation:

Step1: Understand vertical intercept

The vertical intercept (y - intercept) of a line in the form \( e = mt + b \) (where \( e \) is elevation, \( t \) is time, \( m \) is slope, and \( b \) is vertical intercept) is the value of \( e \) when \( t = 0 \).

Step2: Find elevation at \( t = 0 \)

From the problem, when the plane starts to descend, \( t = 0 \) minutes. The elevation at this time is given as 2,500 feet. Also, from the graph, when \( t = 0 \), the point on the graph has an elevation of 2500 feet.

Answer:

2500