Question

△ijk is reflected across the y-axis to produce △ijk. write the rule for the reflection. (x, y) → (\square, \square)

Explanation:

Step1: Recall reflection rule over y - axis

The rule for reflecting a point \((x,y)\) across the \(y\) - axis is \((x,y)\to(-x,y)\).

Step2: Verify with example points

Take point \(J\) with coordinates \((- 3,-1)\). After reflection across the \(y\) - axis, using the rule \((x,y)\to(-x,y)\), we get \((-(-3),-1)=(3,-1)\) which is the coordinate of \(J'\). Similarly, for point \(I(-7,-8)\), after reflection \((-(-7),-8)=(7,-8)\) (coordinate of \(I'\)) and for \(K(-1,-5)\), \((-(-1),-5)=(1,-5)\) (coordinate of \(K'\)).

Answer:

\((x,y)\to(-x,y)\)