Question

identify the genotype for each numbered item. 1. 2. 3. done

Explanation:

Step1: Analyze the row and column headers

The row headers are \(RY\), \(Ry\), \(rY\), \(ry\) and the column headers are \(RY\), \(Ry\), \(rY\), \(ry\). For a cell in a Punnett square, the genotype is formed by combining the allele from the row and the column.

Step2: Determine genotype for item 1

For item 1, the row is \(RY\) and the column is \(Ry\). Combining these, we get \(RRYy\) (since \(R\times R = RR\) and \(Y\times y=Yy\)).

Step3: Determine genotype for item 2

For item 2, the row is \(Ry\) and the column is \(ry\). Combining these, we get \(Rryy\) (since \(R\times r = Rr\) and \(y\times y = yy\)).

Step4: Determine genotype for item 3

For item 3 (assuming it's the row label \(ry\)), but if we consider the cell where row is \(ry\) and column is \(rY\) (if that's the intended one - since the problem might have a typo in numbering), combining \(ry\times rY\) gives \(rrYy\) ( \(r\times r=rr\) and \(y\times Y = Yy\)).

Answer:

1. \(RRYy\)
2. \(Rryy\)
3. \(rrYy\)