Question

hydrogen (h₂) and oxygen (o₂) combine to make water (h₂o) in the following equation
6h₂ + 3o₂ → ?h₂o
how many water molecules would be produced?
(1 point)
three
six
five
four

Explanation:

Step1: Count hydrogen atoms on the left - hand side

The left - hand side has \(6H_2\), so the number of hydrogen atoms is \(6\times2 = 12\).

Step2: Count oxygen atoms on the left - hand side

The left - hand side has \(3O_2\), so the number of oxygen atoms is \(3\times2=6\).

Step3: Determine the formula of water

Water is \(H_2O\). Let the number of water molecules be \(x\). The number of hydrogen atoms in \(xH_2O\) is \(2x\) and the number of oxygen atoms is \(x\).

Step4: Set up equations based on atom conservation

For hydrogen: \(2x = 12\) (since hydrogen atoms are conserved), solving for \(x\) gives \(x=\frac{12}{2}=6\). For oxygen: \(x = 6\) (since oxygen atoms are \(6\) on the left - hand side and \(x\) on the right - hand side in \(H_2O\)).

Answer:

B. six