Question

$$ f ( x ) = \frac { \sin ( x ) } { x } $$
how would you rewrite $$ f ( x ) $$ so it can be differentiated using the
power rule?
assume

$$ x \ eq 0 $$

.
choose 1 answer:
a $$ x ^ { - 1 } \sin ( x ) $$
b $$ \sin ( x ) \cdot \frac { 1 } { - } $$

Explanation:

Step1: Recall the negative exponent rule

The negative exponent rule states that \(a^{-n}=\frac{1}{a^{n}}\) for \(a
eq0\) and integer \(n\). Here, \(\frac{1}{x}=x^{- 1}\) since \(n = 1\).

Step2: Rewrite the function

Given \(f(x)=\frac{\sin(x)}{x}\), using the negative - exponent rule, we can rewrite it as \(f(x)=x^{-1}\sin(x)\)

Answer:

A. \(x^{-1}\sin(x)\)