Question

how much longer is the hypotenuse of the triangle than its shorter leg?

Explanation:

Step1: Find the hypotenuse

Use the Pythagorean theorem \(a^{2}+b^{2}=c^{2}\), where \(a = 6\) and \(b = 8\).
\(6^{2}+8^{2}=c^{2}\)
\(36 + 64=c^{2}\)
\(100=c^{2}\)
\(c = 10\)

Step2: Calculate the difference

Subtract the length of the shorter leg (\(6\)) from the hypotenuse (\(10\)).
\(10-6=4\)

Answer:

\(4\) ft