Question

how many real solutions does $x^2 + 4x + 4 = 0$ have? options: infinite, two, one repeated, none

Explanation:

Step1: Recall discriminant formula

For quadratic equation \(ax^2 + bx + c = 0\), discriminant \(D = b^2 - 4ac\).
Here, \(a = 1\), \(b = 4\), \(c = 4\).

Step2: Calculate discriminant

\(D = 4^2 - 4\times1\times4 = 16 - 16 = 0\).

Step3: Determine real solutions

If \(D = 0\), quadratic has one repeated real solution.

Answer:

One repeated