Question

how many hydrogen (h) atoms can be found on both sides of the balanced chemical equation below?
c5h12 + 8o2 --> 5co2 +6h2o

Explanation:

Step1: Analyze the left side

On the left side, there is \(C_5H_{12}\). The subscript of \(H\) is \(12\), so there are \(12\) hydrogen atoms from \(C_5H_{12}\). \(O_2\) has no hydrogen atoms.

Step2: Analyze the right side

On the right side, there is \(6H_2O\). Each \(H_2O\) molecule has \(2\) hydrogen atoms. So the number of hydrogen atoms from \(H_2O\) is \(6\times2 = 12\). \(5CO_2\) has no hydrogen atoms.

Answer:

\(12\)