Question

how many atoms of zn are present in 10.0 moles of zinc? 6.02 x 10^{23} atoms zn 1.66 x 10^{-23} atoms zn 6.02 x 10^{22} atoms zn 6.02 x 10^{24} atoms zn

Explanation:

Step1: Recall Avogadro's number

Avogadro's number \( N_A=6.02\times 10^{23}\text{ atoms/mol}\)

Step2: Use the formula \(N = n\times N_A\)

Given \(n = 10.0\space mol\) of \(Zn\). Substitute into the formula: \(N=(10.0\space mol)\times(6.02\times 10^{23}\text{ atoms/mol})\)

Step3: Calculate the number of atoms

\(N = 6.02\times10^{24}\text{ atoms}\)

Answer:

\(6.02\times 10^{24}\text{ atoms Zn}\)