QUESTION IMAGE
Question
hotdogs and hamburgers can be cooked on a propane grill. propane (c₃h₈) is a combustible gas that burns in oxygen gas (o₂) to produce heat, carbon dioxide (co₂), and water vapor (h₂o). this reaction is represented by the balanced chemical equation below.
c₃h₈ (g) + 5o₂ (g) → 3co₂ (g) + 4h₂o (g)
determine the number of each type of atom in the reactants and products.
number of atoms in reactants number of atoms in products
c
h 8 8
o
Step1: Calculate the number of carbon atoms in reactants
In the reactant \(C_3H_8\), the subscript of \(C\) is \(3\). There is no other carbon - containing reactant. So the number of \(C\) atoms in reactants is \(3\).
Step2: Calculate the number of carbon atoms in products
In the product \(3CO_2\), for each \(CO_2\) molecule, there is \(1\) \(C\) atom. Since the coefficient of \(CO_2\) is \(3\), the number of \(C\) atoms in products is \(3\times1 = 3\).
Step3: Calculate the number of oxygen atoms in reactants
In the reactant \(5O_2\), for each \(O_2\) molecule, there are \(2\) \(O\) atoms. Since the coefficient of \(O_2\) is \(5\), the number of \(O\) atoms in reactants is \(5\times2=10\).
Step4: Calculate the number of oxygen atoms in products
In the product \(3CO_2\), for each \(CO_2\) molecule, there are \(2\) \(O\) atoms. The coefficient of \(CO_2\) is \(3\), so the number of \(O\) atoms from \(CO_2\) is \(3\times2 = 6\). In the product \(4H_2O\), for each \(H_2O\) molecule, there is \(1\) \(O\) atom. The coefficient of \(H_2O\) is \(4\), so the number of \(O\) atoms from \(H_2O\) is \(4\times1=4\). The total number of \(O\) atoms in products is \(6 + 4=10\).
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| Number of atoms in reactants | Number of atoms in products | |
|---|---|---|
| \(H\) | \(8\) | \(8\) |
| \(O\) | \(10\) | \(10\) |