Question

a hockey puck moves 28 meters southward, then 14 meters northward, and finally 4 meters southward. for this motion, what is the distance moved? distance (m) = what is the magnitude and direction of the displacement? magnitude (m) = dirn =

Explanation:

Step1: Calculate the distance

Distance is the total length of the path.
$$28 + 14+4$$

Step2: Calculate the displacement

Let southward be positive. Displacement \(d=(28 - 14 + 4)\)

Answer:

Distance \(=46\) m
Magnitude of displacement \(=18\) m
Dir'n = Southward