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Question
in guinea pigs, short fur (s) is dominant to long fur (s). two heterozygous guinea pigs (ss) mate. complete the punnett square and then list the percentages of the expected genotypes for their offspring. heterozygous guinea pig genotype probability (%) homozygous dominant: heterozygous: homozygous recessive:
Step1: Determine gametes
Each heterozygous guinea pig (Ss) can produce two types of gametes: S and s.
Step2: Create Punnett square
| S | s | |
|---|---|---|
| s | Ss | ss |
Step3: Calculate genotype probabilities
- For homozygous dominant (SS): 1 out of 4 squares, so $\frac{1}{4}= 25\%$
- For heterozygous (Ss): 2 out of 4 squares, so $\frac{2}{4}=50\%$
- For homozygous recessive (ss): 1 out of 4 squares, so $\frac{1}{4}=25\%$
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Homozygous dominant: 25%
Heterozygous: 50%
Homozygous recessive: 25%