Question

a group of data items and their mean are given.
12, 20, 28, 48, 72, 108 ; mean = 48
a. find the deviation from the mean for each of the data items.
b. find the sum of the deviations in part (a).
a. type the deviation from the mean for each of the data items.
12 20 28 48 72 108
-36 -28 -20 0 24 60
(simplify your answers.)
b. the sum of the deviations in part (a) is
(simplify your answer.)

Explanation:

Step1: Recall the formula for deviation

Deviation of a data item \(x\) from the mean \(\bar{x}\) is \(x - \bar{x}\). For part (b), we need to sum up all the deviations from part (a).

Step2: Sum the deviations

We have the deviations: \(-36,-28,-20,0,24,60\).

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Answer:

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