Question

graph the function.
$f(x)=2\sqrt{x + 4}$
plot four points on the graph of the function: the left - most point and three additional points. then click on the graph - a - function button.

Explanation:

Step1: Find the domain

The expression under the square - root must be non - negative. So, $x + 4\geq0$, which gives $x\geq - 4$. The left - most point occurs when $x=-4$.

Step2: Calculate the left - most point

When $x = - 4$, $f(-4)=2\sqrt{-4 + 4}=0$. So the left - most point is $(-4,0)$.

Step3: Choose additional $x$ values

Let $x=-3$, then $f(-3)=2\sqrt{-3 + 4}=2$. The point is $(-3,2)$.
Let $x = 0$, then $f(0)=2\sqrt{0 + 4}=4$. The point is $(0,4)$.
Let $x = 5$, then $f(5)=2\sqrt{5 + 4}=6$. The point is $(5,6)$.

Answer:

The four points are $(-4,0),(-3,2),(0,4),(5,6)$