Question

graph the function.
$f(x)=sqrt3{x + 2}$
plot five points on the graph of the function, as follows.
· plot the first point using the x - value that satisfies $sqrt3{x + 2}=0$.
· plot two points to the left and two points to the right of the first point.
then click on the graph - a - function button.

Explanation:

Step1: Find the first - point x - value

Set $\sqrt[3]{x + 2}=0$. Cubing both sides gives $x+2 = 0$, so $x=-2$. When $x = - 2$, $y=\sqrt[3]{-2 + 2}=0$. The first point is $(-2,0)$.

Step2: Find two points to the left

Let $x=-3$. Then $y=\sqrt[3]{-3 + 2}=\sqrt[3]{-1}=-1$. Let $x=-4$. Then $y=\sqrt[3]{-4 + 2}=\sqrt[3]{-2}\approx - 1.26$. The points are $(-3,-1)$ and $(-4,-\sqrt[3]{2})$.

Step3: Find two points to the right

Let $x=-1$. Then $y=\sqrt[3]{-1 + 2}=1$. Let $x=0$. Then $y=\sqrt[3]{0 + 2}=\sqrt[3]{2}\approx1.26$. The points are $(-1,1)$ and $(0,\sqrt[3]{2})$.

Answer:

Plot the points $(-4,-\sqrt[3]{2}),(-3,-1),(-2,0),(-1,1),(0,\sqrt[3]{2})$ on the graph.