Question

graph the function.
$f(x)=sqrt3{x}-5$
plot five points on the graph of the function, as follows.

• plot the first point using the x - value that satisfies $sqrt3{x}=0$.
• plot two points to the left and two points to the right of the first point.

then click on the graph - a - function button.

Explanation:

Step1: Find the first - point x - value

Set $\sqrt[3]{x}=0$, then $x = 0$. When $x = 0$, $f(0)=\sqrt[3]{0}-5=-5$. So the first point is $(0, - 5)$.

Step2: Find two points to the left of the first point

Let $x=-8$, then $f(-8)=\sqrt[3]{-8}-5=-2 - 5=-7$. The point is $(-8,-7)$.
Let $x = - 1$, then $f(-1)=\sqrt[3]{-1}-5=-1 - 5=-6$. The point is $(-1,-6)$.

Step3: Find two points to the right of the first point

Let $x = 1$, then $f(1)=\sqrt[3]{1}-5=1 - 5=-4$. The point is $(1,-4)$.
Let $x = 8$, then $f(8)=\sqrt[3]{8}-5=2 - 5=-3$. The point is $(8,-3)$.

Answer:

The five points are $(0, - 5),(-8,-7),(-1,-6),(1,-4),(8,-3)$