graph the following function on the axes provided.
$f(x) = \begin{cases} -1 & \text{for} & -4

Question

graph the following function on the axes provided.
$f(x) = \begin{cases} -1 & \text{for} & -4 < x < 1 \\ x + 2 & \text{for} & 1 < x \leq 5 \end{cases}$
click and drag to make a line. click the line to delete it.
click on an endpoint of a line to change it.
graph axes with x from -10 to 10 and y from -10 to 10

Accepted Answer

# Explanation:
## Step1: Graph $ y = - 1$ for $-4<x<1$
This is a horizontal line. When $x=-4$, since $x = - 4$ is not included in the domain $-4<x<1$, we have an open - circle at the point $(-4,-1)$. When $x = 1$, since $x = 1$ is not included in the domain $-4<x<1$, we have an open - circle at the point $(1,-1)$.
## Step2: Graph $y=x + 2$ for $1<x\leq5$
Find two points on the line. When $x=1$, since $x = 1$ is not included in the domain $1<x\leq5$, we have an open - circle at the point $(1,1 + 2)=(1,3)$. When $x = 5$, $y=5+2=7$, so we have a closed - circle at the point $(5,7)$.

# Answer:
Graph a horizontal line $y=-1$ with open - circles at $(-4,-1)$ and $(1,-1)$ for $-4<x<1$, and graph the line $y=x + 2$ with an open - circle at $(1,3)$ and a closed - circle at $(5,7)$ for $1<x\leq5$.

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Question

Explanation:

Step1: Graph \( y = - 1\) for \(-4
This is a horizontal line. When \(x=-4\), since \(x = - 4\) is not included in the domain \(-4
Step2: Graph \(y=x + 2\) for \(1
Find two points on the line. When \(x=1\), since \(x = 1\) is not included in the domain \(1

Step2: Graph \(y=x + 2\) for \(1
Find two points on the line. When \(x=1\), since \(x = 1\) is not included in the domain \(1

Answer: