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in the given figure, which lines are parallel? justify your answer. det…

Question

in the given figure, which lines are parallel? justify your answer. determine the pairs of parallel lines. choose the correct answer below. a. $overleftrightarrow{ce} parallel overleftrightarrow{ch}$ by the converse of the alternate interior angles theorem b. $overleftrightarrow{ce} parallel overleftrightarrow{ek}$ by the converse of the alternate interior angles theorem c. $overleftrightarrow{hk} parallel overleftrightarrow{ch}$ by the converse of the same-side interior angles postulate d. $overleftrightarrow{ch} parallel overleftrightarrow{ek}$ by the converse of the corresponding angles theorem e. $overleftrightarrow{hk} parallel overleftrightarrow{ek}$ by the converse of the alternate exterior angles theorem f. $overleftrightarrow{ce} parallel overleftrightarrow{hk}$ by the converse of the same-side interior angles theorem

Explanation:

Brief Explanations

To determine parallel lines, we use angle - related theorems (Alternate Interior Angles, Corresponding Angles, etc.). For option F, when we consider lines \(\overline{CE}\) and \(\overline{HK}\), the same - side interior angles formed by a transversal will satisfy the Converse of the Same - Side Interior Angles Theorem (if same - side interior angles are supplementary, lines are parallel). Let's analyze other options:

  • Option A: \(\overline{CE}\) and \(\overline{CH}\) are not parallel as they intersect.
  • Option B: \(\overline{CE}\) and \(\overline{EK}\) intersect, so not parallel.
  • Option C: \(\overline{HK}\) and \(\overline{CH}\) intersect, not parallel.
  • Option D: \(\overline{CH}\) and \(\overline{EK}\) - the reasoning about Corresponding Angles does not hold as they are not set up for that theorem.
  • Option E: \(\overline{HK}\) and \(\overline{EK}\) intersect, not parallel.

Only option F has lines \(\overline{CE}\parallel\overline{HK}\) justified by the Converse of the Same - Side Interior Angles Theorem.

Answer:

F. \(\overline{CE}\parallel\overline{HK}\) by the Converse of the Same - Side Interior Angles Theorem