Question

given the electron configurations shown, drag the lewis structures to show the number of valence electrons for all the period 2 elements. electron configuration 1s²2s¹ 1s²2s² 1s²2s²2p¹ 1s²2s²2p² 1s²2s²2p³ 1s²2s²2p⁴ 1s²2s²2p⁵ 1s²2s²2p⁶ valence electrons 1 2 3 4 5 6 7 8 lewis symbols li· ·be· ·b· ·c· :n· :o· :f· :ne:

Explanation:

Step1: Identify valence electrons

For period 2 elements, valence electrons are in the \(2s\) and \(2p\) orbitals.

• For \(1s^{2}2s^{1}\) (Li), valence electrons \(= 1\) (from \(2s^{1}\)), Lewis symbol: \(Li\cdot\)
• For \(1s^{2}2s^{2}\) (Be), valence electrons \(= 2\) (from \(2s^{2}\)), Lewis symbol: \(\cdot Be\cdot\)
• For \(1s^{2}2s^{2}2p^{3}\) (N), valence electrons \(=2 + 3=5\) (from \(2s^{2}2p^{3}\)), Lewis symbol: \(:\dot{N}\cdot\)
• For \(1s^{2}2s^{2}2p^{5}\) (F), valence electrons \(=2 + 5 = 7\) (from \(2s^{2}2p^{5}\)), Lewis symbol: \(:\ddot{F}\cdot\)
• For \(1s^{2}2s^{2}2p^{6}\) (Ne), valence electrons \(=2+6 = 8\) (from \(2s^{2}2p^{6}\)), Lewis symbol: \(:\ddot{Ne}:\)

Answer:

Lewis symbols: \(Li\cdot\), \(\cdot Be\cdot\), \(:\dot{N}\cdot\), \(:\ddot{F}\cdot\), \(:\ddot{Ne}:\)