Question

did i get this
a balloon contains 1.65 mol of argon gas and has a volume of 0.750 l. upon the addition of additional argon gas the balloon expands to 1.85 l. how much argon gas was added, assuming the temperature and pressure remain constant?
0.840 mol
2.42 mol
4.07 mol
0.669 mol

Explanation:

Step1: Apply Avogadro's law

Avogadro's law is \( \frac{V_1}{n_1}=\frac{V_2}{n_2} \), where \( V_1 = 0.750\ L \), \( n_1=1.65\ mol \), \( V_2 = 1.85\ L \), and \( n_2 \) is the final number of moles.

Step2: Solve for \( n_2 \)

$$
LATEXBLOCK0
$$

Step3: Calculate the moles of gas added

The moles of gas added \( \Delta n=n_2 - n_1 \).

$$
LATEXBLOCK1
$$

Answer:

2.42 mol