Question

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a 50.0 g piece of metal gains 2020 j of energy when it is heated from 25.0 ^ { \circ } c to 115.0 ^ { \circ } c. what is
the specific heat of the metal?
j/g ^ { \circ } c
what is the possible identify of the metal from the previous question? specific heats of common
substances
lead
copper
gold
iron
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Explanation:

Step1: Calculate the temperature change

The formula for temperature change is $\Delta T=T_{final}-T_{initial}$.
Given $T_{initial} = 25.0^{\circ}C$ and $T_{final}=115.0^{\circ}C$, so $\Delta T=115.0 - 25.0=90.0^{\circ}C$.

Step2: Use the heat - formula to find specific heat

The heat formula is $Q = mc\Delta T$, where $Q$ is the heat energy, $m$ is the mass, $c$ is the specific heat, and $\Delta T$ is the temperature change.
We need to solve for $c$, so $c=\frac{Q}{m\Delta T}$.
Given $Q = 2020\ J$, $m = 50.0\ g$, and $\Delta T=90.0^{\circ}C$.
Substitute the values: $c=\frac{2020}{50.0\times90.0}$.
First, calculate the denominator: $50.0\times90.0 = 4500$.
Then, $c=\frac{2020}{4500}\approx0.45\ J/g^{\circ}C$.

Answer:

The specific heat of the metal is approximately $0.45\ J/g^{\circ}C$.
For the identification part, the specific heat of iron is approximately $0.45\ J/g^{\circ}C$. So the metal is iron.