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Question
are functions 1 and 2 the same? explain.
function 1: ( y = 3(x + 5) )
function 2: y equals three times x, plus 5.
a no. ( 3(x + 5) = 15x ) and \three times x, plus 5\ would be ( 3x + 5 ).
b yes, ( 3(x + 5) ) and \three times x, plus 5\ are both equal to ( 15x ).
c yes, ( 3(x + 5) ) and \three times x, plus 5\ are both equal to ( 3x + 5 ).
d no. ( 3(x + 5) = 3x + 15 ) and \three times x, plus 5\ would be ( 3x + 5 ).
Step1: Expand Function 1
Using the distributive property \( a(b + c)=ab + ac \), for \( y = 3(x + 5) \), we get \( y=3x+3\times5 = 3x + 15 \).
Step2: Translate Function 2 to Algebraic Form
"Three times \( x \), plus 5" translates to \( y = 3x+5 \).
Step3: Compare the Two Functions
Function 1 simplifies to \( 3x + 15 \) and Function 2 is \( 3x + 5 \). So they are not the same. Now check the options:
- Option A: \( 3(x + 5)=15x \) is wrong (correct is \( 3x + 15 \)).
- Option B: Both equal to \( 15x \) is wrong.
- Option C: Both equal to \( 3x + 5 \) is wrong (Function 1 is \( 3x + 15 \)).
- Option D: Correctly states \( 3(x + 5)=3x + 15 \) and Function 2 is \( 3x + 5 \), so they are not the same.
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D. No. \( 3(x + 5)=3x + 15 \) and "three times \( x \), plus 5" would be \( 3x + 5 \).