Question

fully simplify.
$(4x^4 + y^4)^2$
answer attempt 1 out of 5

Explanation:

Step1: Recall the square of a binomial formula

The formula for \((a + b)^2\) is \(a^2 + 2ab + b^2\). Here, \(a = 4x^4\) and \(b = y^4\).

Step2: Calculate \(a^2\)

\(a^2=(4x^4)^2 = 4^2\times(x^4)^2=16x^8\)

Step3: Calculate \(2ab\)

\(2ab = 2\times(4x^4)\times(y^4)=8x^4y^4\)

Step4: Calculate \(b^2\)

\(b^2=(y^4)^2 = y^8\)

Step5: Combine the terms

\((4x^4 + y^4)^2=16x^8 + 8x^4y^4 + y^8\)

Answer:

\(16x^8 + 8x^4y^4 + y^8\)