Question

a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow pears. event a: green event b: pear p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.

Explanation:

Step1: Calculate total fruits

Total = 20 + 6 + 14 + 10 = 50

Step2: Find P(A) (green fruits)

Green fruits = 6 + 14 = 20, so $P(A) = \frac{20}{50} = 0.4$

Step3: Find P(B) (pears)

Pears = 14 + 10 = 24, so $P(B) = \frac{24}{50} = 0.48$

Step4: Find P(A and B) (green pears)

Green pears = 14, so $P(A \cap B) = \frac{14}{50} = 0.28$

Step5: Compute P(A or B)

$P(A \cup B) = 0.4 + 0.48 - 0.28 = 0.6$

Answer:

0.60