Question

formula of the unsaturated hydrocarbon is:
a) ch₃ - ch₂ - ch ≡ ch - ch₂ - ch₃
b) ch₃ - c = c - ch ≡ ch - ch₂
c) ch₃ - ch₂ - c ≡ c - ch₂ - ch₃
d) ch₃ - ch = ch - ch₂ - ch₂ - ch₃
e) ch₃ - c = c - ch₂ - ch₂ - ch₃
question 10 / 1 point

Explanation:

Step1: Check the number of carbon atoms

Each option should have 6 carbon atoms.

• Option a: \(CH_3 - CH_2 - CH\equiv CH - CH_2 - CH_3\) has 6 carbon atoms.
• Option b: \(CH_3 - C = C - CH\equiv CH - CH_2\) has 6 carbon atoms but the last \(CH_2\) is not a valid end - group (should be \(CH_3\) to satisfy carbon's tetravalency).
• Option c: \(CH_3 - CH_2 - C\equiv C - CH_2 - CH_3\) has 6 carbon atoms.
• Option d: \(CH_3 - CH = CH - CH_2 - CH_2 - CH_3\) has 6 carbon atoms.
• Option e: \(CH_3 - C = C - CH_2 - CH_2 - CH_3\) has 6 carbon atoms.

Step2: Check carbon valency

Carbon has a valency of 4.

• In option a: Each carbon atom has 4 bonds.
• In option b: The last \(CH_2\) group has a carbon atom with only 3 bonds (violates carbon's tetravalency).
• In option c: Each carbon atom has 4 bonds.
• In option d: Each carbon atom has 4 bonds.
• In option e: Each carbon atom has 4 bonds.

Step3: Check for unsaturation

Unsaturated hydrocarbons have double or triple bonds.

• Option a has a triple bond (\(C\equiv C\)) and is an alkyne (unsaturated).
• Option c has a triple bond (\(C\equiv C\)) and is an alkyne (unsaturated).
• Option d has a double bond (\(C = C\)) and is an alkene (unsaturated).
• Option e has a double bond (\(C = C\)) and is an alkene (unsaturated).

Since the question is about a general unsaturated hydrocarbon (could be alkene or alkyne), and all options a, c, d, e have the correct number of carbon atoms and satisfy carbon valency. But if we assume a more common case (if no other information is given), alkenes and alkynes are both unsaturated. However, if we check for the most'standard' structure:

• Option a: \(CH_3 - CH_2 - CH\equiv CH - CH_2 - CH_3\) (hex - 3 - yne)
• Option c: \(CH_3 - CH_2 - C\equiv C - CH_2 - CH_3\) (hex - 2 - yne)
• Option d: \(CH_3 - CH = CH - CH_2 - CH_2 - CH_3\) (hex - 2 - ene)
• Option e: \(CH_3 - C = C - CH_2 - CH_2 - CH_3\) (hex - 2 - ene, but with incorrect double - bond placement notation, it should be \(CH_3 - CH = CH - CH_2 - CH_2 - CH_3\) similar to option d for proper double - bond representation in a linear chain)

Answer:

A. \(CH_3 - CH_2 - CH\equiv CH - CH_2 - CH_3\), C. \(CH_3 - CH_2 - C\equiv C - CH_2 - CH_3\), D. \(CH_3 - CH = CH - CH_2 - CH_2 - CH_3\)