Question

flobbits are an alien species. the table below provides information about some of their physical traits. use your knowledge of genetics to complete the problems below.

characteristic	dominant gene	recessive gene
eye number	one (e)	three (e)
lip color	purple (l)	green (l)
number of fangs	one (f)	two (f)

1. use the information about flobbits to fill in the phenotype for each trait.

a. tt ______
b. ll ______
c. ee ______
d. ee ______

1. use the information in the chart to write the genotypes for each trait below.

a. one eye ______
b. two fangs ______
c. short ______
d. purple lips ______

1. determine the genotypes using the information in the chart above.

a. heterozygous purple lips ______
b. homozygous one eye ______
c. hybrid one fang ______
d. purebred tall ______

1. a tall flobbit named george met and fell in love with a tall flobbit named marge.

a. if marge’s father is a heterozygous tall flobbit and her mother is a short flobbit, what is marge’s genotype? complete the punnett square to show the possible genotypes that would result to help you determine marge’s genotype.
what is marge’s genotype? ______
b. george is heterozygous for this height.
what is his genotype? ______
c. complete the punnett square to show the possibilities that would result if george and marge had offspring.
d. list the possible genotypes and phenotypes for the kids.
______
e. what is the probability of tall flobbit kids? ______%
f. what is the probability of short flobbit kids? ______%

Explanation:

Step1: Solve Part 1 (Phenotypes)

• For A (TT): Dominant gene for height is Tall (T), so homozygous dominant (TT) phenotype is Tall.
• For B (IL): Wait, typo? Should be Ll? Dominant for lip color is Purple (L), so Ll (or IL if typo) phenotype is Purple Lips.
• For C (ee): Recessive for eye number is Three (e), homozygous recessive (ee) phenotype is Three Eyes.
• For D (Ee): Dominant for eye number is One (E), heterozygous (Ee) phenotype is One Eye.

Step2: Solve Part 2 (Genotypes from Phenotypes)

• A (One eye): Dominant is E, so possible genotypes EE or Ee.
• B (Two fangs): Recessive is f, so genotype ff.
• C (Short): Recessive is t, so genotype tt.
• D (Purple lips): Dominant is L, so possible genotypes LL or Ll.

Step3: Solve Part 3 (Genotypes from Descriptions)

• A (Heterozygous purple lips): Heterozygous means one dominant and one recessive, so Ll.
• B (Homozygous one eye): Homozygous dominant for eye number (E), so EE.
• C (Hybrid one fang): Hybrid = heterozygous, dominant for fangs is F, so Ff.
• D (Purebred tall): Purebred = homozygous dominant, so TT.

Step4: Solve Part 4A (Marge's Genotype)

• Marge's father: heterozygous tall (Tt), mother: short (tt). Punnett square:
• Father's gametes: T, t; Mother's gametes: t, t.
• Offspring: Tt, Tt, tt, tt. But Marge is tall (since she's a tall flobbit), so her genotype is Tt (because tt is short, and Tt is tall).

Step5: Solve Part 4B (George's Genotype)

• Heterozygous for height: Tt (one T, one t).

Step6: Solve Part 4C (Punnett Square for George (Tt) and Marge (Tt))

• George's gametes: T, t; Marge's gametes: T, t.
• Punnett square:

	T	t
t	Tt	tt

Step7: Solve Part 4D (Genotypes and Phenotypes)

• Genotypes: TT, Tt, Tt, tt.
• Phenotypes: TT (Tall), Tt (Tall), Tt (Tall), tt (Short). So Tall (TT, Tt, Tt) and Short (tt).

Step8: Solve Part 4E (Probability of Tall Kids)

• Tall genotypes: TT, Tt, Tt (3 out of 4). Probability: $\frac{3}{4} \times 100 = 75\%$.

Step9: Solve Part 4F (Probability of Short Kids)

• Short genotype: tt (1 out of 4). Probability: $\frac{1}{4} \times 100 = 25\%$.

Answer:

s (Key Parts):

1. A. Tall; B. Purple Lips; C. Three Eyes; D. One Eye
2. A. EE or Ee; B. ff; C. tt; D. LL or Ll
3. A. Ll; B. EE; C. Ff; D. TT

4A. Tt
4B. Tt
4C. Punnett square as above (TT, Tt, Tt, tt)
4D. Genotypes: TT, Tt, Tt, tt; Phenotypes: Tall, Tall, Tall, Short
4E. 75%
4F. 25%

(Note: For full detailed answers, each sub-question's answer is as derived above.)