QUESTION IMAGE
Question
in flies, long wings (w) are dominant to short wings (w). two homozygous recessive flies are crossed.
homozygous recessive fly
phenotype
probability (%)
long wings:
short wings:
Step1: Determine the genotypes of the parents
The parents are homozygous recessive. So their genotypes are \(ww\) and \(ww\).
Step2: Create the Punnett square
| \(w\) | \(w\) | |
|---|---|---|
| \(w\) | \(ww\) | \(ww\) |
Step3: Calculate the probabilities
All the offspring have the genotype \(ww\). Since short wings (\(w\)) is recessive, and there is no \(W\) allele (dominant for long wings) in any of the offspring.
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Long Wings: \(0\%\)
Short Wings: \(100\%\)