Question

find the sum.
\left(\frac{7}{4}x - 5\
ight) + (2y - 3.5) + \left(-\frac{1}{4}x + 5\
ight) = \square

Explanation:

Step1: Combine like terms for x

We have \(\frac{7}{4}x\) and \(-\frac{1}{4}x\). Adding them together: \(\frac{7}{4}x + (-\frac{1}{4}x) = \frac{7 - 1}{4}x = \frac{6}{4}x = \frac{3}{2}x\)

Step2: Combine like terms for constants

The constant terms are \(-5\), \(-3.5\), and \(5\). Adding them: \(-5 - 3.5 + 5 = -3.5\)

Step3: The term with y remains as is

The term with y is \(2y\)

Step4: Combine all terms

Putting it all together: \(\frac{3}{2}x + 2y - 3.5\) (or we can write \(\frac{3}{2}x\) as \(1.5x\), so \(1.5x + 2y - 3.5\))

Answer:

\(\frac{3}{2}x + 2y - 3.5\) (or \(1.5x + 2y - 3.5\))