Question

find the quotient using the standard algorithm.
\\(\

$$\begin{array}{r}\\ ?\\text{ r }\\square\\\\13\\enclose{longdiv}{157}\\\\ \\end{array}$$

\\)

Explanation:

Step1: Divide 15 by 13

13 goes into 15 once (since \(13\times1 = 13\)). Write 1 above the 5 in 157.

Step2: Subtract 13 from 15

\(15 - 13 = 2\). Bring down the 7 to make 27.

Step3: Divide 27 by 13

13 goes into 27 twice (since \(13\times2 = 26\)). Write 2 next to the 1 above the division bar.

Step4: Subtract 26 from 27

\(27 - 26 = 1\). This is the remainder.

Step5: Combine the quotient digits

The quotient digits are 1 and 2, so the quotient is 12 with a remainder of 1.

Answer:

The quotient is 12 and the remainder is 1, so the answer is \(12\) R \(1\) (or in the box for the quotient: \(12\), remainder box: \(1\)).