QUESTION IMAGE
Question
find the perimeter.
write your answer as a fraction or as a whole or mixed number.
diagram of a parallelogram with side lengths 4/15 m, 2/15 m, 4/15 m, 2/15 m
blank meters
submit
Step1: Recall Perimeter Formula for Parallelogram
A parallelogram has opposite sides equal. So perimeter \( P = 2\times(\text{length} + \text{width}) \). Here, length is \( \frac{4}{15}\,m \) and width is \( \frac{2}{15}\,m \).
Step2: Substitute Values into Formula
First, find the sum of length and width: \( \frac{4}{15} + \frac{2}{15} = \frac{4 + 2}{15} = \frac{6}{15} \). Then multiply by 2: \( P = 2\times\frac{6}{15} = \frac{12}{15} \). Simplify the fraction: \( \frac{12\div3}{15\div3} = \frac{4}{5} \)? Wait, no, wait. Wait, actually, the sides are two of \( \frac{4}{15} \) and two of \( \frac{2}{15} \). So perimeter is \( 2\times\frac{4}{15} + 2\times\frac{2}{15} \). Let's calculate that. \( 2\times\frac{4}{15} = \frac{8}{15} \), \( 2\times\frac{2}{15} = \frac{4}{15} \). Then sum: \( \frac{8}{15} + \frac{4}{15} = \frac{12}{15} = \frac{4}{5} \)? Wait, no, \( 12\div3 = 4 \), \( 15\div3 = 5 \). Wait, but let's check again. The sides: two sides of \( \frac{4}{15} \) and two sides of \( \frac{2}{15} \). So perimeter is \( \frac{4}{15} + \frac{2}{15} + \frac{4}{15} + \frac{2}{15} \). Combine like terms: \( (\frac{4}{15} + \frac{4}{15}) + (\frac{2}{15} + \frac{2}{15}) = \frac{8}{15} + \frac{4}{15} = \frac{12}{15} = \frac{4}{5} \)? Wait, no, \( 12\div3 = 4 \), \( 15\div3 = 5 \). Wait, but \( \frac{12}{15} \) simplifies to \( \frac{4}{5} \)? Wait, 12 and 15 have a GCD of 3. 12÷3=4, 15÷3=5. So yes. Wait, but let's do it step by step.
Wait, the parallelogram has four sides: two of length \( \frac{4}{15} \) meters and two of length \( \frac{2}{15} \) meters. So perimeter \( P = 2\times\frac{4}{15} + 2\times\frac{2}{15} \).
Calculate \( 2\times\frac{4}{15} = \frac{8}{15} \).
Calculate \( 2\times\frac{2}{15} = \frac{4}{15} \).
Now add them: \( \frac{8}{15} + \frac{4}{15} = \frac{8 + 4}{15} = \frac{12}{15} \).
Simplify \( \frac{12}{15} \) by dividing numerator and denominator by 3: \( \frac{12\div3}{15\div3} = \frac{4}{5} \)? Wait, no, wait, \( \frac{12}{15} \) is equal to \( \frac{4}{5} \)? Wait, 12 divided by 3 is 4, 15 divided by 3 is 5. Yes. So the perimeter is \( \frac{4}{5} \) meters? Wait, no, wait, that can't be. Wait, let's check the addition again. \( \frac{4}{15} + \frac{2}{15} + \frac{4}{15} + \frac{2}{15} \). Let's add the numerators: 4 + 2 + 4 + 2 = 12. Denominator is 15. So \( \frac{12}{15} \), which simplifies to \( \frac{4}{5} \). Yes, because 12 and 15 are both divisible by 3. So 12 ÷ 3 = 4, 15 ÷ 3 = 5. So the perimeter is \( \frac{4}{5} \) meters? Wait, no, wait, maybe I made a mistake. Wait, the sides: the top and bottom are \( \frac{4}{15} \), left and right are \( \frac{2}{15} \). So perimeter is 2(4/15 + 2/15) = 2(6/15) = 12/15 = 4/5. Yes, that's correct.
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\(\frac{4}{5}\)