Question

find the 29th term of this arithmetic sequence. -24, -16, -8, 0, 8, ... a_{29} = ? hint: a_n = a_1 + (n - 1)d

Explanation:

Step1: Identify known values

$a_1=-24$, $n=29$, $d=-16-(-24)=8$

Step2: Substitute into arithmetic formula

$a_{29} = -24 + (29-1)\times8$

Step3: Simplify the expression

$a_{29} = -24 + 28\times8 = -24 + 224$

Step1: Identify known values

$a_1=-24$, $n=29$, $d=-16-(-24)=8$

Step2: Substitute into arithmetic formula

$a_{29} = -24 + (29-1)\times8$

Step3: Calculate the product first

$28\times8=224$

Step4: Compute final term

$a_{29} = -24 + 224$

Answer:

199
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