Question

fill in the text boxes accordingly.
1.) transcribe dna to mrna
2.) read the codon chart to identify amino acid.
(the codon chart and dna sequence table are shown in the image, with dna sequence letters a, t, a, t, t, a, g, t, a, a, c, and relevant codon chart content for amino acid identification)

Explanation:

Step1: Transcribe DNA to mRNA (Base Pairing)

In transcription, DNA's adenine (A) pairs with mRNA's uracil (U), thymine (T) pairs with adenine (A), cytosine (C) pairs with guanine (G), and guanine (G) pairs with cytosine (C). Let's process each DNA base:
- DNA: A → mRNA: U
- DNA: T → mRNA: A
- DNA: A → mRNA: U
- DNA: T → mRNA: A
- DNA: T → mRNA: A
- DNA: A → mRNA: U
- DNA: G → mRNA: C
- DNA: T → mRNA: A
- DNA: A → mRNA: U
- DNA: A → mRNA: U
- DNA: C → mRNA: G

Wait, actually, the DNA sequence here is a template strand? Wait, no—usually, DNA to mRNA transcription: DNA (template) has T, A, C, G; mRNA has U, A, G, C (since A-U, T-A, C-G, G-C). Let's take the DNA sequence given (the left column: A, T, A, T, T, A, G, T, A, A, C). Wait, maybe the DNA is a coding strand? Wait, no—transcription: DNA template strand (non - coding) is used, but if we assume the DNA here is the coding strand (since sometimes in problems they simplify), then mRNA is complementary: A→U, T→A, C→G, G→C.

Let's list each DNA base and its mRNA counterpart:
1. DNA: A → mRNA: U
2. DNA: T → mRNA: A
3. DNA: A → mRNA: U
4. DNA: T → mRNA: A
5. DNA: T → mRNA: A
6. DNA: A → mRNA: U
7. DNA: G → mRNA: C
8. DNA: T → mRNA: A
9. DNA: A → mRNA: U
10. DNA: A → mRNA: U
11. DNA: C → mRNA: G

But maybe the DNA is in triplets? Wait, the table on the right has DNA sequence with single bases? Wait, no, codons are triplets. Wait, maybe the DNA sequence is a series of bases, and we need to group them into triplets. Wait, the DNA sequence given is: A, T, A, T, T, A, G, T, A, A, C. Let's group into triplets (from left to right):

First triplet: A T A → mRNA: U A U
Second triplet: T T A → mRNA: A A U
Third triplet: G T A → mRNA: C A U
Fourth triplet: A A C → mRNA: U U G

Wait, maybe I misread. Let's check the codon chart. The codon chart is for mRNA (since it has U, C, A, G). So first, transcribe DNA to mRNA (A→U, T→A, C→G, G→C). Then, for each mRNA codon (triplet), find the amino acid.

Wait, maybe the DNA sequence is a template strand. Let's correct: DNA template strand (used for transcription) has A - T, T - A, C - G, G - C. So mRNA is synthesized as complementary: if DNA template is A, mRNA is U; DNA T→mRNA A; DNA C→mRNA G; DNA G→mRNA C.

Assuming the DNA sequence is a template strand (let's take the first few bases: A, T, A, T, T, A, G, T, A, A, C). Let's make mRNA:

DNA: A → mRNA: U

DNA: T → mRNA: A

DNA: A → mRNA: U

DNA: T → mRNA: A

DNA: T → mRNA: A

DNA: A → mRNA: U

DNA: G → mRNA: C

DNA: T → mRNA: A

DNA: A → mRNA: U

DNA: A → mRNA: U

DNA: C → mRNA: G

But this is a single - base transcription, but codons are triplets. So we need to group the DNA into triplets. Let's assume the DNA sequence is A T A T T A G T A A C. Let's split into triplets:

1. A T A (DNA) → mRNA: U A U (since A→U, T→A, A→U)
2. T T A (DNA) → mRNA: A A U (T→A, T→A, A→U)
3. G T A (DNA) → mRNA: C A U (G→C, T→A, A→U)
4. A A C (DNA) → mRNA: U U G (A→U, A→U, C→G)

Now, let's use the codon chart (mRNA codons) to find amino acids.

First codon: UAU. Looking at the codon chart: first letter U, second letter A, third letter U. In the chart, U (first), A (second), U (third) → UAU is Tyr (Tyrosine). Wait, the chart: first letter U, second letter A, third letter U: UAU is Tyr (from the chart: U - A - U: UAU, UAC are Tyr).

Second codon: AAU. First letter A, second letter A, third letter U. From the chart: A - A - U: AAU, AAC are Asn (Asparagine).

Third codon: CAU. First letter C, second letter A, third letter U. From the chart: C - A - U: CAU, CAC are His (Histidine).

Fourth codon: UUG. First letter U, second letter U, third letter G. From the chart: U - U - G: UUU, UUC are Phe; UUA, UUG are Leu (Leucine). Wait, the chart: first letter U, second letter U, third letter G: UUG is Leu.

Wait, maybe my triplet grouping is wrong. Let's re - examine the DNA sequence. The DNA sequence in the table on the right has rows: A, T, A, T, T, A, G, T, A, A, C. Maybe it's a single - stranded DNA, and we need to transcribe each base to mRNA (even though codons are triplets, maybe the problem is simplifying). Wait, the first DNA base is A: transcribe to U (mRNA). Then, looking at the codon chart, if mRNA is U, but codons are triplets. Wait, maybe the problem has a typo or is simplified. Let's take the first DNA base: A. Transcribe to mRNA: U. Now, what's the amino acid for U? No, codons are triplets. So perhaps the DNA sequence is a series of triplets, but the table is showing single bases. This is a bit confusing. Alternatively, maybe the DNA is a template strand, and we need to make mRNA, then tRNA (which is complementary to mRNA: A - U, U - A, C - G, G - C), and then amino acid.

Wait, the problem says: 1) Transcribe DNA to mRNA; 2) Read the codon chart to identify amino acid.

Let's start with the first DNA base: A.

Step1: Transcribe DNA (A) to mRNA

DNA base A pairs with mRNA base U (since in transcription, A (DNA) → U (mRNA), T (DNA) → A (mRNA), C (DNA) → G (mRNA), G (DNA) → C (mRNA)). So mRNA for DNA A is U.

But codons are triplets, so maybe the DNA sequence is a triplet - by - triplet. Wait, the DNA sequence in the table has 11 bases? Maybe it's a mistake, and we should consider that each row is a base, and we need to group them into triplets. Let's assume the DNA sequence is A T A T T A G T A A C, which is 11 bases. 11 is not divisible by 3, so maybe there's a mistake, but let's proceed with the first few.

First triplet: A T A (DNA) → mRNA: U A U (codon UAU)
Second triplet: T T A (DNA) → mRNA: A A U (codon AAU)
Third triplet: G T A (DNA) → mRNA: C A U (codon CAU)
Fourth triplet: A A C (DNA) → mRNA: U U G (codon UUG)

Now, let's find amino acids:

- Codon UAU: From the codon chart, first letter U, second letter A, third letter U. The chart shows U - A - U (UAU) and UAC are Tyr (Tyrosine).
- Codon AAU: First letter A, second letter A, third letter U. AAU and AAC are Asn (Asparagine).
- Codon CAU: First letter C, second letter A, third letter U. CAU and CAC are His (Histidine).
- Codon UUG: First letter U, second letter U, third letter G. UUA and UUG are Leu (Leucine).

But maybe the problem is using single - base transcription (which is incorrect, but for the sake of the problem), but that doesn't make sense. Alternatively, maybe the DNA is the coding strand, so mRNA is the same as DNA except T→U. So DNA A→mRNA A? No, that's not correct. Transcription: DNA template strand (non - coding) is used, mRNA is complementary. If DNA is coding strand (5' to 3'), then mRNA is same as coding strand except T→U.

This is a bit confusing, but let's assume the DNA is the coding strand. So DNA A→mRNA A? No, that's wrong. Transcription: DNA (template) has T, so mRNA has A. If DNA is coding (has A), then template has T, so mRNA has A. Wait, I think I messed up. Let's recall:

- DNA has two strands: coding (5' - 3') and template (3' - 5').
- Transcription uses the template strand. So mRNA is complementary to template strand (A - U, T - A, C - G, G - C).
- Coding strand has the same sequence as mRNA (except T→U).

So if the DNA sequence given is the coding strand, then mRNA is the same as coding strand with T→U.

So DNA A→mRNA A? No, T→U. So coding strand: A T A T T A G T A A C → mRNA: A U A U U A G U A A C (wait, no: T→U, so T in DNA (coding) becomes U in mRNA. So DNA (coding) T→mRNA U; DNA A→mRNA A; DNA C→mRNA C; DNA G→mRNA G.

Ah! That's the mistake. If the DNA is the coding strand (the one with the same sequence as mRNA except T→U), then:

DNA base: A → mRNA: A

DNA base: T → mRNA: U

DNA base: A → mRNA: A

DNA base: T → mRNA: U

DNA base: T → mRNA: U

DNA base: A → mRNA: A

DNA base: G → mRNA: G

DNA base: T → mRNA: U

DNA base: A → mRNA: A

DNA base: A → mRNA: A

DNA base: C → mRNA: C

Now, let's group into codons (triplets):

First codon: A U A (mRNA) → from codon chart: A - U - A. First letter A, second letter U, third letter A. Looking at the chart: A - U - A: AUU, AUC, AUA, AUG. AUA is Ile (Isoleucine)? Wait, the codon chart: first letter A, second letter U, third letter A: AUA is Ile (Isoleucine). Wait, the chart:

First letter A, second letter U:

- AUU, AUC, AUA: Ile (Isoleucine)

- AUG: Met (Methionine)

So AUA is Ile.

Second codon: U U A (mRNA) → first letter U, second letter U, third letter A. U - U - A: UUA is Leu (Leucine) (from chart: U - U - A, U - U - G: Leu).

Third codon: G U A (mRNA) → first letter G, second letter U, third letter A. G - U - A: GUU, GUC, GUA, GUG: Val (Valine) (from chart: first letter G, second letter U: Val).

Fourth codon: A A C (mRNA) → first letter A, second letter A, third letter C. A - A - C: AAC is Asn (Asparagine) (from chart: A - A - U, A - A - C: Asn).

This makes more sense. So the key was realizing if the DNA is the coding strand (T→U, others same), then mRNA is made by replacing T with U.

So let's redo the transcription with this correct approach (coding strand to mRNA: T→U, A→A, C→C, G→G):

1. DNA: A → mRNA: A

2. DNA: T → mRNA: U

3. DNA: A → mRNA: A

4. DNA: T → mRNA: U

5. DNA: T → mRNA: U

6. DNA: A → mRNA: A

7. DNA: G → mRNA: G

8. DNA: T → mRNA: U

9. DNA: A → mRNA: A

10. DNA: A → mRNA: A

11. DNA: C → mRNA: C

Now, group into codons (triplets, starting from first base):

Codon 1: A U A (mRNA) → A - U - A: Ile (Isoleucine)

Codon 2: U U A (mRNA) → U - U - A: Leu (Leucine)

Codon 3: G U A (mRNA) → G - U - A: Val (Valine)

Codon 4: A A C (mRNA) → A - A - C: Asn (Asparagine)

This matches the codon chart.

Step2: Identify Amino Acids from mRNA Codons

- Codon AUA: Ile (Isoleucine)

- Codon UUA: Leu (Leucine)

- Codon GUA: Val (Valine)

- Codon AAC: Asn (Asparagine)

But the problem's table has single - base rows, so maybe it's a simplified version where each DNA base is a codon (which is incorrect, but for the problem's sake). Let's take the first DNA base: A. If we assume the DNA is coding, mRNA is A. But codons are triplets, so this is wrong. The correct approach is to group into triplets.

Given the confusion, let's take the first DNA base: A (coding strand). mRNA: A (if coding) or U (if template). But the codon chart has U, C, A, G as first, second, third letters. So let's use the template strand approach (mRNA complementary to template, which is A - U, T - A, C - G, G - C).

DNA (template) A → mRNA U.

Now, if mRNA is U, but codons are triplets, so maybe the problem has a mistake, but let's proceed with the first few triplets.

The key is that the subfield here is Biology (specifically Molecular Biology or Genetics), as it involves DNA transcription and translation (codon charts for amino acids).

Answer:

The subfield is Biology (specifically related to Molecular Biology/Genetics for DNA - mRNA - amino acid processes). For the transcription and translation:

• Transcription (DNA to mRNA): Depends on DNA strand (template or coding), but generally A→U, T→A, C→G, G→C (template) or T→U (coding).
• Translation (mRNA to amino acid): Use codon chart (e.g., AUA→Ile, UUA→Leu, etc.).