Question

on a field trip, there will be 1 chaperone for every 11 students. a bus has room for 60 passengers. principal rodriguez wants to know how many chaperones and students to assign to each bus.
y = 11x
complete the table to show the number of students for each number of chaperones.
chaperones (x) | students (y)
3 | ?
4 | ?
5 | ?
6 | ?

Explanation:

Step1: For x = 3

We use the equation \( y = 11x \). Substitute \( x = 3 \) into the equation.
\( y = 11\times3 = 33 \)

Step2: For x = 4

Substitute \( x = 4 \) into \( y = 11x \).
\( y = 11\times4 = 44 \)

Step3: For x = 5

Substitute \( x = 5 \) into \( y = 11x \).
\( y = 11\times5 = 55 \)

Step4: For x = 6

Substitute \( x = 6 \) into \( y = 11x \).
\( y = 11\times6 = 66 \) (But we should check if total passengers (chaperones + students) exceed 60. Wait, the table is just for number of students given chaperones, so we proceed with the calculation. However, in reality, for x=6, total passengers would be 6 + 66 = 72 > 60, but the table is just about the relationship \( y = 11x \) for the given x values.)

Answer:

For Chaperones (x) = 3, Students (y) = 33;
For Chaperones (x) = 4, Students (y) = 44;
For Chaperones (x) = 5, Students (y) = 55;
For Chaperones (x) = 6, Students (y) = 66.

(If we consider the bus capacity, we might need to find the valid x where \( x + 11x \leq 60 \) i.e., \( 12x \leq 60 \) so \( x \leq 5 \). But the table asks to complete for x=3,4,5,6 using the equation \( y = 11x \), so the answers based on the equation are as above.)