Question

factor: $9x^2 + 6x - 3x - 2$
options:
$x(9x + 6 - 3) - 2$
$(3x + 2)(3x - 1)$
$(3x - 2)(3x - 1)$
$(3x + 2)(3x + 1)$
the movement of the progress bar may be uneven because questions can be worth more or less (including zero) depending on your

Explanation:

Step1: Group terms

We have the polynomial \(9x^{2}+6x - 3x - 2\) (rewriting \(-3x-2\) as \(+6x-3x - 2\) to group). Group the first two terms and the last two terms: \((9x^{2}+6x)+(-3x - 2)\)

Step2: Factor out GCF from groups

Factor out \(3x\) from the first group: \(3x(3x + 2)\), and factor out \(- 1\) from the second group: \(-1(3x + 2)\)

Step3: Factor out common binomial

Now we have \(3x(3x + 2)-1(3x + 2)\), factor out \((3x + 2)\) to get \((3x + 2)(3x-1)\)

Answer:

C. \((3x + 2)(3x - 1)\) (assuming the third option is C as per the order of options: first option A, second B, third C, fourth D)