Question

express tan p as a fraction in simplest terms.
(there is a right triangle pqr with right angle at q. the length of qr is 15, and the length of qp is 29.)

Explanation:

Step1: Recall tangent definition

In a right triangle, $\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}$ to angle $\theta$.
For $\angle P$, opposite side is $RQ = 15$, adjacent side is $PQ = 29$.

Step2: Apply tangent formula

$\tan P = \frac{\text{opposite to } P}{\text{adjacent to } P} = \frac{RQ}{PQ} = \frac{15}{29}$.

Answer:

$\frac{15}{29}$