Question

exercise question 2
while heating two different samples of water at sea level, one boils at 102°c and one boils at 99.2°c. calculate the percent error for each sample from the theoretical 100.0°c.

Explanation:

Step1: Recall the formula for percent error

The formula for percent error is $Percent\ Error=\frac{\vert Experimental\ Value - Theoretical\ Value\vert}{Theoretical\ Value}\times100\%$

Step2: Calculate percent error for the sample that boils at $102^{\circ}C$

Substitute Experimental Value = $102^{\circ}C$ and Theoretical Value = $100.0^{\circ}C$ into the formula:

$$\begin{align*} Percent\ Error&=\frac{\vert102 - 100.0\vert}{100.0}\times100\%\\ &=\frac{2}{100.0}\times100\%\\ & = 2\% \end{align*}$$

Step3: Calculate percent error for the sample that boils at $99.2^{\circ}C$

Substitute Experimental Value = $99.2^{\circ}C$ and Theoretical Value = $100.0^{\circ}C$ into the formula:

$$\begin{align*} Percent\ Error&=\frac{\vert99.2 - 100.0\vert}{100.0}\times100\%\\ &=\frac{\vert- 0.8\vert}{100.0}\times100\%\\ &=\frac{0.8}{100.0}\times100\%\\ &=0.8\% \end{align*}$$

Answer:

The percent error for the sample that boils at $102^{\circ}C$ is $2\%$ and for the sample that boils at $99.2^{\circ}C$ is $0.8\%$